№1
Дано: m(NaCl) = 1,5 г
Найти: N - ?; V - ?; n - ?;
№2
Дано: N(Al2O3) = 9*10^23
Найти: n - ?; m - ?; V - ?;
№3
Дано: n(O2) = 1,1 моль
Найти: N - ?; m - ?; V - ?;
№4
Дано: V(Ca(OH)2) = 75 л
Найти: N - ?; m - ?; n - ?;

1.даноm(NaCL) = 1.5 g---------------------------N-?V-?n-?M(NaCL) = 58.5 g/moln(NaCL)= m/M= 1.5/58.5 = 0.026 molV(NaCL) = n*Vm = 0.026*22.4 = 0.5824 LN(NaCL)=n*N(A) = 0.026*6.02*10^23 = 1.5652*10^22  молекул2 . даноN(Al2O3)=9*10^23 молекул----------------------n-? m-? V-?M(Al2O3) = 102 g/moln(Al2O3) = N(AL2O3) / N(A) = 9*10^23 / 6.02*10^23 = 1.5 molm(Al2O3) = n(Al2O3)*M(AL2O3) = 1.5*102 = 153 gV(Al2O3)= n(Al2O3)*Vm =1.5*22.4 = 33.6 L3. даноn(O2)= 1.1 mol---------------------------N-? m-? V-?M(O2)=32 g/molN(O2) = n(O2) * N(A) = 1.1*6.02*10^23 = 6.622*10^23 молекулm(O2) = n(O2)*M(O2) = 1.1*32= 35.2 gV(O2) = n(O2)*Vm = 1.1*22.4 = 24.64 g4.даноV(Ca(OH)2) = 75 L-----------------------N-? m-? n-?M(Ca(OH)2)= 74 g/moln(Ca(OH)2) = V(Ca(OH)2) / Vm = 75/22.4= 3.35 molN(Ca(OH)2)= n(Ca(OH)2)*N(A) = 3.35*6.02*10^23 = 2.0167*10^24 молекулm(Ca(OH)2)= n(Ca(OH)2)*M(Ca(OH)2) = 3.35*74= 247.9 g