how many grams nitric acid can be obtained from 2 mol ammoniac

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np

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Have:n(NH₃) - 2 molTo find: m(HNO₃)Solve:The ratio of ammonia to nitric acid is 1:1NH₃ → HNO₃n(HNO₃) = 2 molm(HNO₃) = n(HNO₃) · M(HNO₃) = 2 · (1+14+16·3) = 2 · 63 = 126 g/molAnswer: m(HNO₃) = 126 g/mol