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расставьте коэффициенты в данном уравнении и составьте уравнения в полном и сокращенном ионном виде CuSO4+KOH=K2SO4+Cu(OH)2
Ответы 4
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что изменилось
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Автор:
eliasdekv - 5 лет назад
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0
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2koh
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Автор:
puckavery - 5 лет назад
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0
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всё что могу только коэффициенты.
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Автор:
helensharp - 5 лет назад
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0
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CuSO4+2KOH=K2SO4+Cu(OH)2
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Автор:
gabriellaking - 5 лет назад
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0
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