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для полного гидрирования 90 г пропина расходуется водород объемом (л)
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Предмет:
Химия -
Автор:
estherscze - 4 года назад
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Ответы 1
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C3H4 + 2H2 = C3H8 N(C3H4)= 90/40 =2.25 моль N(H2)=2.25 x 2=4.5 моль v(H2)= N xVm= 4.5 x 22.4 =100.8 л
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Автор:
gingerwalton - 4 года назад
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