w(C) =53.33%
w(H) =15.56%
w(N)=31.11%
D(Ne)=2.25
Найти:CxHyNz

CxHyNz = rD(r)(Ne) = 2.25 ==> M(r) = 2.25 * 20 = 45 г/мольn(C) = (53.33*45)/1200 = 2n(H) = (15.56*45)/100 = 7n(N) = (31.11*45)/1400 = 1C2H7N;NH2C2H5 — этиламин.