При разложении 40 г перманганата калия выделился кислород. Рассчитайте массу образовавшегося кислорода.

При разложении 40 г перманганата калия выделился кислород. Рассчитайте массу образовавшегося кислорода.
- Предмет:
  Химия
- Автор:
  acevedo
- 5 лет назад

Ответы 3

Спасибо большое:)))
- Автор:
  kyliednmc
- 5 лет назад
- 0
2KMnO4 = K2MnO4 + MnO2 + O2
m(KMnO4) = 40 g
M(KMnO4) = 39 + 55 + 64 = 158 g/mol
n(KMnO4) = 40 / 158 = 0.253164 mol
n(O2) = n(KMnO4) / 2 = 0.1265822
M(O2) = 16 * 2 = 32 g/mol
m(O2) = 32 * 0.1265822 = 4.050632911 g
- Автор:
  maddox
- 5 лет назад
- 0
40 г. Х г 2KMnO4. ->K2MnO4. + MnO2. + O2n=2 моль. n=1 мольМ= 158 г/моль. М=32 г/мольm=316 г. m=32 г40 г KMnO4. -. Х г О2316 г KMnO4. -. 32 г О2m(O2)=40*32/316=4 г
- Автор:
  tough guyigbi
- 5 лет назад
- 0
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При разложении 40 г перманганата калия выделился кислород. Рассчитайте массу образовавшегося кислорода.

Ответы 3

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