m (NaOH)=30г; m(H2SO4)=49г; Мф(соли)=?; m(соли)=?

дано

m (NaOH)=30г

m(H2SO4)=49г

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Мф(соли)=?

m(соли)=?

M(NaOH) = 40 g/mol

n(NaOH) = m/M = 30 / 40 = 0.75 mol

M(H2SO4) = 98 g/mol

n(H2SO4) = m/M = 49 / 98 = 0.5 mol

n(NaOH) > n(H2SO4)

2NaOH+H2SO4-->Na2SO4+2H2O

M(Na2SO4) = 142 g/mol

n(H2SO4) = n(Na2SO4) = 0.5 mol

m(Na2SO4) = n*M = 0.5 * 142 = 71 g

ответ 142 г/моль,  71 г