14-9x+x² решите пж.................... - Znanija.Site

14-9x+x² решите пж
....................
- Предмет:
  Химия
- Автор:
  alfredjsde
- 5 лет назад

Ответы 1

${x}^{2} - 9x + 14 = 0$ а=1, b=-9, c=14 ${b}^{2} - 4ac = ( - 9)^{2} - 4 \times 1 \times 14 = 81 - 56 =25$ $x1 = \frac{ - b + \sqrt{d} }{2a} = \frac{ 9 + 5}{2} = \frac{14}{2} = 7$ $x2 = \frac{9 - 5}{2} = \frac{4}{2} = 2$ Ответ: Х1=7; Х2=2
- Автор:
  gusn2ag
- 5 лет назад
- 0
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