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К 100 г 70% раствора уксусной кислоты добавили 30 моль воды. Определите массовую долю уксусной кислоты в образовавшемся растворе.
Ответы 1
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Ответ: 1,094%
Объяснение:
m(H2O) = n*M =30 моль*18 г/моль = 540 г
m(CH3COOH) = 100 г*0,07 = 7 г
m₂(p-pa CH3COOH) = 100 г + 540 г = 640 г
ω₂(СН3СООН) = 7 г*100%/640 г = 1,094%-
Автор:
titan10 - 5 лет назад
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