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С какими из перечисленных веществ взаимодействует Na2CO3 : магний,раствор азотной кислоты,гидроксид кальция (раствор), сульфат калия,вода оксид калия, хлорид бария? Запишите возможные уравнения реакций( два из них запишите в молекулярном и в ионном виде).
Ответы 1
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Объяснение:
Na₂CO₃+ Мg= не возможно
Na₂CO₃+ 2HCl = 2NaCl+CO₂+H₂O
Na₂CO₃+Ca(OH)₂=CaCO₃↓+2NaOH
2Na⁺+CO₃²⁻+Ca²⁺+2OH⁻=CaCO₃↓+2Na⁺+2OH⁻
Ca²⁺CO₃²⁻=CaCO₃↓
Na₂CO₃+K₂SO₄= не возможно
Na₂CO₃+ H₂O = не возможно
Na₂CO₃+ K₂O = не возможно
Na₂CO₃+ BaCl₂=2NaCl+BaCO₃↓
2Na⁺+CO₃²⁻+Ba²⁺+2Cl⁻=2Na⁺+2Cl⁻+BaCO₃↓
Ba²⁺CO₃²⁻=BaCO₃↓
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Автор:
little bearmnxu - 5 лет назад
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