what is the mass of 2 moles of iron hydroxide​

M(Fe(OH)2)= 56 + 32 + 2 = 90 g/mol

M(Fe(OH)3)= 56 + 48 + 3 = 107 g/mol

m(Fe(OH)2)= 90*2 = 180 g

m(Fe(OH)3)= 107*2 = 214 g