Помогите Сгорело 150 г C5H12.Определить объем воздуха который затратился на горении н.у?

Помогите Сгорело 150 г C5H12.Определить объем воздуха который затратился на горении н.у?
- Предмет:
  Химия
- Автор:
  cutie11
- 5 лет назад

Ответы 1

Дано:
m(C5H12)= 150 г
O2
V(возд)—?
Решение:
C5H12 + 8O2 = 5CO2 + 6H2O
x/179.2 = 150/72
x = 373.3 л О2.
Кислорода в составе воздуха приблизительно 21% ==> составим пропорцию:
373.3 = 21%
y = 100%
373.3/21 = y/100
y = 1777.6 л
Ответ: затратилось 1777.6 литров воздуха.
- Автор:
  valentina80
- 5 лет назад
- 0
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Помогите Сгорело 150 г C5H12.Определить объем воздуха который затратился на горении н.у?​

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Помогите Сгорело 150 г C5H12.Определить объем воздуха который затратился на горении н.у?