Mr (FeCl3) = Ar (Fe) * N (Fe) + Ar (Cl) * N (Cl) = 56 * 1 + 35,5 * 3 = 162,5;ω (Fe в FeCl3) = N (Fe) * Ar (Fe) * 100% / Mr (FeCl3) = 1 * 56 * 100% / 162,5 = 34,46%;
Mr (MgCl2) = Ar (Mg) * N (Mg) + Ar (Cl) * N (Cl) = 24 * 1 + 35,5 * 2 = 95;ω (Mg в MgCl2) = N (Mg) * Ar (Mg) * 100% / Mr (MgCl2) = 1 * 24 * 100% / 95 = 25,26%;
Mr (CaCl2) = Ar (Ca) * N (Ca) + Ar (Cl) * N (Cl) = 40 * 1 + 35,5 * 2 = 111;ω (Ca в CaCl2) = N (Ca) * Ar (Ca) * 100% / Mr (CaCl2) = 1 * 40 * 100% / 111 = 36,04%.
Ответ: вариант 3).
Автор:
boomerharrisonДобавить свой ответ