Определите объем кислорода (н.у.), необходимый для сжигания кальция массой 4 грамм.
Предмет:
ХимияАвтор:
juliethampton2Ca+O2=2CaO
n(O2)=1/2n(Ca)=(4(грамма)/40(грамм/моль))/2=0,05моль
V(O2)=0,05моль*22,4л=1,12л
Ответ:V(O2)=1,12л
Автор:
smarty85Добавить свой ответ
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