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Помогите с задачами!
1.Расчитать объем кислорода собранного при разложении до 147.6г оксида ртути (||)
2. Определить объем амиака которой можно получить 0.68л азота по реакции азота с водородом
3. Расчитать массу гидроксида алюминия и объем сероводорода полученных при взаимодействии 50г сульфида алюминия водой
Ответы 1
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Находим кол-во сульфида алюминия 50:150 = 0,33 моль. Al2S3 +6 H2O =2 Al(OH)3 +3 H2S Количество гидроксида Al будет в два раза больше(2 Al(OH)3) . Сероводорода в три раза больше(3H2S) Масса гидроксида Al: 0,66*78 = 51,48 г Объем сероводорода: 0,99*22,4 = 22,176
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Автор:
biscuitnyth - 5 лет назад
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