количество моль кислорода , требующегося для сжигания 33,6 г кремния - №8738074

количество моль кислорода , требующегося для сжигания 33,6 г кремния
- Предмет:
  Химия
- Автор:
  noodleskgk9
- 6 лет назад

Ответы 1

Si+O2 = SiO2MSi = 28г/мольnO2 = nSi = m/M =33,6/28 =1,2моль
- Автор:
  amethyst
- 6 лет назад
- 0
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