В смеси озона и кислорода объемом 2л. объемная доля озона составляет 10%. Найти массу смеси. Решите пожалйста очень срочно найдо)
2*10/100 = 0,2 л - озона = 8,9*10(-3)моль
1,8л - кислорода = 0,08моль
О2 и О3 - соответственно
масса О2 = 8,9*10(-3) * 32 =0,28г
масса О3=0,08*48 = 3,84г
Автор:
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