Напишите программу, которая определяет, верно ли, что введённое число содержит ровно три одинаковые цифры, а все остальные встречаются только по одному разу (например, как в числе 77237) PascalABC
!решать при помощи while!

А теперь скажите, как это надо было решать :D

VarA,B0,B1,B2,B3,B4,B5,B6,B7,B8,B9:integer;BeginWriteLn('Введите число');ReadLn(A);While A>0 do   Begin   Case A mod 10 of   0:B0:=B0+1;   1:B1:=B1+1;   2:B2:=B2+1;   3:B3:=B3+1;   4:B4:=B4+1;   5:B5:=B5+1;   6:B6:=B6+1;   7:B7:=B7+1;   8:B8:=B8+1;   9:B9:=B9+1;   End;   A:= A div 10;   End;if (B0 = 3)and(B1<2)and(B2<2)and(B3<2)and(B4<2)and(B5<2)and(B6<2)and(B7<2)and(B8<2)and(B9<2)then WriteLn('Верно')else if (B1 = 3)and(B2<2)and(B3<2)and(B4<2)and(B5<2)and(B6<2)and(B7<2)and(B8<2)and(B9<2)and(B0<2)then WriteLn('Верно')else if (B2 = 3)and(B3<2)and(B4<2)and(B5<2)and(B6<2)and(B7<2)and(B8<2)and(B9<2)and(B0<2)and(B1<2)then WriteLn('Верно')else if (B3 = 3)and(B4<2)and(B5<2)and(B6<2)and(B7<2)and(B8<2)and(B9<2)and(B0<2)and(B1<2)and(B2<2)then WriteLn('Верно')else if (B4 = 3)and(B5<2)and(B6<2)and(B7<2)and(B8<2)and(B9<2)and(B0<2)and(B1<2)and(B2<2)and(B3<2)then WriteLn('Верно')else if (B5 = 3)and(B6<2)and(B7<2)and(B8<2)and(B9<2)and(B0<2)and(B1<2)and(B2<2)and(B3<2)and(B4<2)then WriteLn('Верно')else if (B6 = 3)and(B7<2)and(B8<2)and(B9<2)and(B0<2)and(B1<2)and(B2<2)and(B3<2)and(B4<2)and(B5<2)then WriteLn('Верно')else if (B7 = 3)and(B8<2)and(B9<2)and(B0<2)and(B1<2)and(B2<2)and(B3<2)and(B4<2)and(B5<2)and(B6<2)then WriteLn('Верно')else if (B8 = 3)and(B9<2)and(B0<2)and(B1<2)and(B2<2)and(B3<2)and(B4<2)and(B5<2)and(B6<2)and(B7<2)then WriteLn('Верно')else if (B9 = 3)and(B0<2)and(B1<2)and(B2<2)and(B3<2)and(B4<2)and(B5<2)and(B6<2)and(B7<2)and(B8<2)then WriteLn('Верно')else WriteLn('Не верно')End.