Рекурсия . Информатика. Помогите пожалуйста!

1. F(1) = 1 F(2) = 2 * F(1) + 2 + 3 = 2 * 1 + 2 + 3 = 7 F(3) = 2 * F(2) + 3 + 3 = 2 * 7 + 3 + 3 = 20 F(4) = 2 * F(3) + 4 + 3 = 2 * 20 + 4 + 3 = 47 F(5) = 2 * F(5) + 5 + 3 = 2 * 47 + 5 + 3 = 102 F(6) = 2 * F(5) + 6 + 3 = 2 * 102 + 6 + 3 = 213 2. F(1) = 3 F(2) = 2 * F(1) - 2 + 1 = 2 * 3 - 2 + 1 = 5 F(3) = 2 * F(2) - 3 + 1 = 2 * 8 - 3 + 1 = 14 F(4) = 2 * F(3) - 4 + 1 = 2 * 14 - 4 + 1 = 25 F(5) = 2 * F(4) - 5 + 1 = 2 * 25 - 5 + 1 = 46 F(6) = 2 * F(5) - 6 + 1 = 2 * 46 - 6 + 1 = 87 3. F(1) = F(2) = 1 F(3) = F(2) + F(1) + 3 = 1 + 1 + 3 = 5 F(4) = F(3) + F(2) + 4 = 5 + 1 + 4 10 F(5) = F(4) + F(3) + 5 = 10 + 5 + 5 = 20 F(6) = F(5) + F(4) + 6 = 20 + 10 + 6 = 36 F(7) = F(6) + F(5) + 7 = 36 + 20 + 7 = 63