Ответы 1

  • The function would require the following imports:

    go
    import (
    "os"
    "io"
    )


    Here's the implementation of the ModifyFile function:

    go
    func ModifyFile(filename string, pos int64, val string) error {
    file, err := os.OpenFile(filename, os.O_RDWR, 0644)
    if err != nil {
    return err
    }
    defer file.Close()

    _, err = file.Seek (pos, io.SeekStart)
    if err != nil {
    return err
    }

    _, err = file.Write([]byte(val))
    if err != nil {
    return err
    }

    return nil
    }


    The function ModifyFile takes the filename, position, and value as arguments.

    Here's how it works:

    1. The function opens the file with read/write permissions using os.OpenFile and assigns it to the file variable.
    2. The file is then closed using defer to ensure it gets closed after the function returns.
    3. The function uses file.Seek to move the current position in the file to the desired position (pos).
    4. Finally, it writes the new value (val) to the file using file.Write.

    If any error occurs during the process, the function returns the error. Otherwise, it returns nil to indicate success.
    • Автор:

      trevor
    • 1 год назад
    • 0
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