1)Пусть x^2=y, тогда 6x^4+3,6x^2=0 будет равно 6y^2+3,6y=0. 6y(y+0,6)=0y1=0y2=-0,62)x(x^2+3-3,5x)=0x1=0 x^2-3,5x+3=0D=b^2-4ac=12,25-12=0,25т. виетаx3×x2=3x3+x2=3,5x2=1,5x3=23) y^4-y^3-16y^2+16y=0 y^3(y - 1) + 16y(y - 1) = 0 (y - 1)(y^3 + 16y) = 0 y(y-1)(y^2 + 16) = 0 1) y = 0 2) y - 1 = 0 y=1 3) y^2+ 16 = 0 y^2 = -16