срочно!!
определите х, log5 x=2log5 7-4log5 3

log(5) х = 2log(5) 3 + 4*log(25) 7ОДЗ: x>0_____2log(5) 3 = log(5) 3^2 = log(5) 9_____4*log(25) 7 = = 4*log(5^2) 7 == 4*(1\2)*log(5) 7 = = 2*log(5) 7 == log(5) 7^2 == log(5) 49=>log(5) x = log(5) 9 + log(5) 49log(5) x = log(5) 9*49log(5) x = log(5) 441x = 441