найдите производную. e^2x 7e^2x+4 √(3x^2-4x+1) (7x^2+3)^5 - №12581581

найдите производную.
e^2x
7e^2x+4
√(3x^2-4x+1)
(7x^2+3)^5
- Предмет:
  Математика
- Автор:
  alannahfhtv
- 6 лет назад

Ответы 1

y' = 2e^2xy' = 14e^2xy' = 6x-4 = 2(3x-2) = 3x-2 2√(3x²-4x+1) 2√(3x²-4x+1) √(3x²-4x+1)y' = 5(7x²+3)⁴ * (14x)=70x(7x²+3)⁴
- Автор:
  heavenlucas
- 6 лет назад
- 0
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