(13)Найти первообразную функции f(x)=3x^2+2x+1 - №12664156

(13)Найти первообразную функции
f(x)=3x^2+2x+1
- Предмет:
  Математика
- Автор:
  barnett
- 5 лет назад

Ответы 2

f(x)=3x²+2x+1F(x)=3*x²⁺¹/(2+1)+2*x¹⁺¹/(1+1)+1*x+C=3x³/3+2x²/2+x+C=x³+x²+x+C
- Автор:
  chanel3
- 5 лет назад
- 0
$f(x)=3x^2+2x+1\\\\F(x)=\int (3x^2+2x+1)dx=3\cdot \frac{x^3}{3}+2\cdot \frac{x^2}{2}+x+C=x^3+x^2+x+C$
- Автор:
  finleykaks
- 5 лет назад
- 0
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