8/ 1+tg^2x +2|sin x|=5.

1+tg²x=1/cos²x8cos²x+2|sinx|-5=08-8sin²x+2|sinx|-5=08sin²x-2|sinx|-3=01)sinx<0⇒x∈(-π+2πn;2π+2πn,n∈z)sinx=a8a²+2a-3=0D=4+96=100a1=(-2-10)/16=-0,75⇒sinx=-0,75x=π+arcsin0,75+2πn,n∈zx=2π-arcsin0,75+2ππn,n∈Za2=(-2+10)/16=1/2⇒sinx=1/2не удов усл2)sinx≥0⇒x∈[2πn,π+2πn,n∈Z]8a²-2sinx-3=0D=4+96=100a1=(2-10)/16=-1/2⇒sinx=-1/2не удов услa2=(2+10)/16=0,75x=arcsin0,75+2πn,n∈Zx=π-arcsin0,75+2πn,n∈Z