sin(3ПX\2 - П\3)= cos(П\6 - ПX)

sin(3πx/2-π/3)-sin(πx-π/3)=02sin(πx/2)cos(5πx/2-2π/3)=0sin(πx/2)=0⇒πx/2=πn⇒x=2n,n∈Zcos(5πx/2-2π/3)=0⇒5πx/2-2π/3=π/2+πn⇒5πx/2=7π/6+πn⇒x=7/15+2n/5,n∈Z