(4x+3)(4x-3)-(6x-1)^2+18=0 РЕШИТЬ

Решение(4x+3)(4x-3)-(6x-1)^2+18=016x² - 9 - 36x² + 12x - 1 + 18 = 0- 20x² + 12x + 8 = 04x² - 6x - 4 = 0 2x² - 3x - 2 = 0D = 9 + 4*2*2 = 25x₁ = (3 - 5)/4x₁ = -1/2x₂ = ( 3 + 5)/4x₂ = 2Ответ: x₁ = -1/2 ; x₂ = 2