как решить 3x^2-2x-16 - №13207687

как решить 3x^2-2x-16
- Предмет:
  Математика
- Автор:
  libbynixon
- 6 лет назад

Ответы 1

$3x^{2} -2x-16=0$ $D=(-2) ^{2} -4*2*(-16)=4+192=196$ $x1= \frac{2+ \sqrt{196} }{2*3}= \frac{2+14}{6} = \frac{16}{6}=2 \frac{4}{6}= 2\frac{2}{3}$ $x2= \frac{2- \sqrt{196} }{2*3}= \frac{2-14}{6}= -2$ Ответ: $-2; 2\frac{1}{3}$
- Автор:
  chessieie62
- 6 лет назад
- 0
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