При каких значениях ,а разность корней уравнения ах²+х-2=0 равна 3?

D = B^2 - 4ac = 1 - 4 * (-2)*a = 1+8aX1 = (-B+D^(1/2))/2aX2 = (-B-D^(1/2))/2aX2 - X1 = 3((-B+D^(1/2))-(-B-D^(1/2)))/2a(2*D^(1/2))/2a = 3(2*(1+8a)^(1/2))/2a = 3 (1+8a)^1/2 = 3aОДЗ a>= -0.125 Возводим в квадрат1+8a = 9a^29a^2-8a-1 = 0 D = 64 - 4*(-1)*9 = 64+36 = 100A1 = (8+10)/18 = 1A2 = (8-10)/18 = -1/9