3 в степени 2x+1 -10*3 в степени x +3=0

Решение3^(2x + 1) - 10*3^(x) + 3 = 03*3^(2x) - 10*3^(x) + 3 = 03^x = t3t² - 10t + 3 = 0D = 100 - 4*3*3 = 64t₁ = (10 - 8)/6t₁ = 1/3t₂ = (10 + 8)/6t₂ = 33^x = 1/33^x = 3⁻¹x₁ = - 13^x = 3x₂ = 1