решите уравнение2( х^2 +1)+5х=0

2x² + 2 + 5x = 02x² + 5x + 2 = 0D = b² - 4ac = 25 - 4 × 2 × 2 = 25 - 16 = 9 = 3²x1 = ( - 5 + 3) / 4 = - 2/4 = - 0,5x2 = ( - 5 - 3) / 4 = - 2

2x^2+2+5x=02x^2+5x+2=0D=25-16=9x1=(-5-3)/4=-2x2=(-5+3)/4=-0,5