Решите плиз систему:
x^2+y^2=5
x-y=b

x^2-2*x*y+y^2+2*x*y=5x-y=b(x-y)^2+2*x*y=5x-y=bb^2+2*x*y=5x*y=(5-b^2)/2x-y=b bu yerden hem x-i tapyp yerine bahasyny goyyarysx=b+yy*(b+y)-(5-b^2)/2=0y^2+y*b-(5-b^2)/2=02y^2+2y*b-5+b^2=0D=(2b)^2-4*2*(b^2-5)=4*b^2-8*b^2+40=40-4*b^2=4(10-b^2) mundan son bahalaryny yerine goyup alyp bolar