f(x)=2x+1/x^2+x; f/(1)

f'(x)=(x+1)'(x-2)-(x+1)(x-2)'/(x-2)^2=1(x-2)-(x+1)1/(x-2)^2=(x-2)-(x+1)/(x-2)^2=x-2-x-1/(x-2)^2=-3/(x-2)^2f'(0)=-3/4