Даны векторы a(x1, y1) и b(x2, y2). Найти скалярное произведение векторов (2a-3b) и (a+2b). x1=4 y1=-1 x2=1 y2-1 - №15375287

Даны векторы a(x1, y1) и b(x2, y2). Найти скалярное произведение векторов (2a-3b) и (a+2b).

x1=4 y1=-1 x2=1 y2-1
- Предмет:
  Математика
- Автор:
  evagriffin
- 5 лет назад

Ответы 1

a{4;-1}, b{1;-1}(2a-3b) {2*4-3*1;2*(-1)-3*(-1)}. {5;1}(a+2b) {4+2*1;-1+2*(-1)}. {6;-3}(2a-3b)*(a+2b)=5*6+1*(-3)=30-3=27
- Автор:
  cupcakegtkk
- 2 года назад
- 8
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