Решите уравнение : (2x-1)^2=2x-1,

(x-3)^2=4(x-3), 4(x-3)^2=(2x+6)^2, (3x+4)^2=3(x+4)

1. 4х - 2=2х-14х-2х=2-12х=1х=0,5 или 1/22. 2х-6=4х-122х-4х=6-12-2х=-6х=33.(4х-12)^2=4х+128х-24=4х=128х-4х=12+244х=36х=94.6х+8=3х+126х-3х=12-82х=4х2