Решите
(X+1)(x+2)-(x+3)(x+4)=0

(х+1)(х+2) - (х+3)(х+4)=0(х²+2х+х+2)- (х²+4х+3х+12)=0х²+3х+2 - х²-7х-12=0(х²-х²)+(3х-7х)+(2-12)=0-4х-10=0-4х=10х=- 10/4х=- 2,5Проверим: (-2,5+1)(-2,5+2)-(-2,5+3)(-2,5+4)=0-1,5*(-0,5) - (0,5*1,5)=00,75-0,75=00=0

(1x × 2x) - (3x × 4x) = 02x - 12x = 0-10x = 0x = - 10 x