многоэтажные дроби
пж
вычислите

1\4\5;

1\1\2;

1\5⅔;

1\7\8;

1\9\10;

1\8\11

1\4\5 = 1*5\4 = 5\4 = 1 1\41\1\2= 1*2\1 = 21\5⅔ = 1/17\3 = 1*3\17 = 3\171\7\8 = 1*8\7 = 8\7 = 1 1\71\9\10 = 1*10\9 = 10\9 = 1 1\91\8\11 = 1*11\8 = 11\8 = 1 3\8

1) можно решить так: 1:4/5 то=>1\4\5 = 1*5\4 = 5\4 = 1 1\41\1\2= 1*2\1 = 21\5⅔ = 1/17\3 = 1*3\17 = 3\171\7\8 = 1*8\7 = 8\7 = 1 1\71\9\10 = 1*10\9 = 10\9 = 1 1\91\8\11 = 1*11\8 = 11\8 = 1 3\8если 1/4:5 то=>2)1\4\5=1/4*1/5=1/201\1\2=1/2=0,51\5⅔=1/5*3/2=3/10=0,31\7\8=1/7*1/8=1/561\9\10=1/9*1/10=1/901\8\11=1/8*1/11=1/88