Сравни сумму и разность дробей с 1 1/7+7/8 2/3-4/27 25/7-7/5 5/6+7/9 3/47/12 18/12-11/9 2/13+3/4 5/13-17/52 31/12+17/24

Ответы 1

$\frac{1}{7} + \frac{7}{8} = \frac{1*8}{56} + \frac{7*7}{56} = \frac{8+49}{56} = \frac{57}{56}=1 \frac{1}{56}; \ 1 \frac{1}{56} \ \textgreater \ 1\\ \frac{2}{3} - \frac{4}{27} = \frac{2*9}{27} - \frac{4}{27} = \frac{18-4}{27}= \frac{14}{27} ; \ \frac{14}{27}\ \textless \ 1\\ \frac{25}{7} - \frac{7}{5} =3 \frac{4}{7} -1 \frac{2}{5} =2 \frac{4}{7} - \frac{2}{5} = \frac{18}{7}- \frac{2}{5}= \frac{18*5}{35} - \frac{2*7}{35} = \frac{90-14}{35} =\\= \frac{76}{35} =2 \frac{6}{35} ; \ 2 \frac{6}{35}\ \textgreater \ 1\\$ $\frac{5}{6} + \frac{7}{9}= \frac{5*3}{18} + \frac{7*2}{18} = \frac{15+14}{18} = \frac{19}{18} =1 \frac{1}{18} ; \ 1 \frac{1}{18} \ \textgreater \ 1\\ \frac{18}{12} - \frac{11}{9} = \frac{18*3}{36} -\frac{11*4}{36} =\frac{54-44}{36} =\frac{10}{36} ; \ \frac{10}{36}\ \textless \ 1\\ \frac{2}{13} +\frac{3}{4}=\frac{2*4}{52} +\frac{3*13}{52} =\frac{8+39}{52} =\frac{47}{52}; \ \frac{47}{52} \ \textless \ 1\\ \frac{5}{13} -\frac{17}{52} =\frac{5*4}{52} -\frac{17}{52} =\frac{20-17}{52} =\frac{3}{52}; \ \frac{3}{52} \ \textless \ 1\\$ $\frac{31}{12}+ \frac{17}{24} = \frac{31*2}{24} +\frac{17}{24} =\frac{62+17}{24}=\frac{79}{24} =3 \frac{7}{24} ; \ 3\frac{7}{24} \ \textless \ 1$
- Автор:
  burnett
- 6 лет назад
- 0
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