Решите уравнения :
121a² - 25 = 0
(1 - 2b)(1+2b)+4b(b-2)=49
(x-2)³+(x+2)³=2(x-3)(x²+3x+9)

1) 121a²  - 25 =0(11a-5)(11a+5)=011a-5=0a=5/1111a+5=0a=-5/112) (1-2b)(1+2b)+4b(b-2)=49(1-4b² )+4b² -8b=491-8b=4948=-8bb=-63)(x-2)³+(x+2)³=2(x-3)(x²+3x+9)(x³-6x²+12x-8)+(x³+6x²+12x+8)=(2x-6)(x²+3x+9)=2x³+6x²+18x-6x²-18x-54=2x³-542x³+24x=2x³-54 x³+12x=x³-27x³+12x-x³+27=012x=-27x=-27/12=-2.25