Помогите!
1-sin^2 x/2=0

1-sin²(x/2)=0(1-sin(x/2))*(1+sin9x/2))=01-sin(x/2)=0 или 1+sin(x/2)=01. 1-sin(x/2)=0. sin(x/2)=1.   x/2=π/2+2πn, n∈Z |*2x₁=π+4πn, n∈Z2. 1+sin(x/2)=0. sin(x/2)=-1.   x/2=-π/2+2πn, n∈Z |*2x₂=-π+4πn, n∈Z