уравнение прямой при точках А (3;2)В(-1;-5)

A(3,2),B(-1,-5)k=tg a = (y2-y1)/(x2-x1), k = (-5-2)/(-1-3)=-7/-4 = 7/4y-y1 = k(x-x1)y-2=7/4(x-3), 4y-8 = 7x-21, 7x-4y-13=0