Помогите срооочно решить!Докажите, что сумма четырёх последовательных натуральных чисел, кратных 3, при делении на 12 дает остаток, равный 6 + во вложениях № 7 смотрите внизу и чуть в верху на втором листе
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МатематикаАвтор:
berlynnn5zh( n/3 + (n+1)/3 +(n+2)/3 + (n+3)/3 ) / 12 = .. дальше сам.
№7
а) 24 - 5 +3х =21; 3x=2; x=2/3
б) 10x - 7x - 5 = -29; 3x = -24; x=-8
в) 1 - 8x - 2x-7 =32; 6x=38; x=38/6
г) -5y + 15 + 11y +2y +1 = 0; 8y=-16; y=-2
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