((3)/(9-х²)+(1)/(х-3)):(х)/(х²-6х+9)=

(3)/(9-х²)+(1)/(х-3)):(х)/(х²-6х+9)1.(3/(9-х²)+1)/(х-3)=3/(3+х)(3-х)+1/(х-3)= 3/(3+х)(3-х)-1/(3-х)=(3-3-х)/ (3+х)(3-х) =-х/ (3+х)(3-х)=х/(3+х)(х-3) 2. (х/(3+х)(х-3)): (х)/(х²-6х+9)= (х/(3+х)(х-3))(х-3)²/х=(х-3)/(х+3)