решите уравнение 2x-2y=4; 5x+y=22

2x-2y=42(х-у)=4х-у=4:2х-у=2х=у+2у=х-25*х+у=22y + 5*x = 22(y + 5*x)/xx = 22 / ((y + 5*x)/x)x = 22/5 - y/5y = 22 / ((y + 5*x)/y)y=−5x+22