Решите уравнение f'=0, если f(x)=(x-1)(x2+1)(x+1) Заранее спасибо. P.S. вторая скобка - №18999863

Решите уравнение f'=0, если f(x)=(x-1)(x2+1)(x+1)
Заранее спасибо.
P.S. вторая скобка (x2+1) это икс в квадрате.
- Предмет:
  Математика
- Автор:
  annabel31
- 5 лет назад

Ответы 1

f(x)= $(x-1)(x^{2}+1)(x+1)=( x^{2} -1)( x^{2} +1)= x^{4}-1$ f'= $4x^{3}$ =0 => x=0
- Автор:
  compton
- 5 лет назад
- 0
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