решите уравнения (-5×-3)(2×-1)=0

(-5x -3)(2x -1) =0-10x^2 +5x -6x +3 =0-10x^2 -x +3 =0, *(-1)10x^2 +x -3 =0D =b^2 -4ac,(a =10, b =1, c = -3)D =1 +4*10*3 =121 =11^2x1,x2=(-b+-корень изD)/2ax1 =(-1 -11)/20 = -0.6x2 =(-1 +11)/20 =0.5ответ: x= -0.6, x =0.5