Помоги решить логарифмическое уравнение!
log0.8 ( 3x^2 + x + 4 ) = log0.8 ( 17x+1 )
log4 ( x-4 ) +log4 ( x+4 ) = log4 ( 3x+2)
log3 (3x+5) + log3 (2x-5) = log3 ( 10x -16)

log0.8 ( 3x^2 + x + 4 ) = log0.8 ( 17x+1 ) {17x+1>0⇒x>-1/17{3x²+x+4>0⇒x∈R,D=1-48=-47<0x∈(-1/17;∞)3x²+x+4=17x+13x²-16x+3=0D=256-36=220x1=(16-2√55)/6 U x2=(16+2√55(/2 log4 ( x-4 ) +log4 ( x+4 ) = log4 ( 3x+2){x-4>0⇒x>4x+4>0⇒x>-4{3x+2>0⇒x>-2/3x∈(4;∞)log(3)(x²-16)=log(4)(3x+2)x²-16=3x+2x²-3x-18=0x1+x2=3 u x1*x2=-18x1=-3 не удов услх2=6 log3 (3x+5) + log3 (2x-5) = log3 ( 10x -16) {3x+5>0⇒x>-5/3{2x-5>0⇒x>2,5{10x-16>0⇒x>1,6x∈(2,5;∞)log(3)[(3x+5)(2x-5)]=log(3)(10x-16)6x²-15x+10x-25=10x-166x²-15x-9=02x²-5x-3=0D=25+24=49x1=(5-7)/4=-0,5 не удов услх2=(5+7)/4=3