решите уравнение (√2x^2-14x+21)^2+4^2=x^2

( √ 2x² - 14x + 21 )² + 4² = x²2x² - 14x + 21 + 16 = x²x² - 14x + 47 = 0D = 196 - 188 = 8 ; √ D = 2√2 x1 = ( 14 + 2√2 ) : 2 = 7 + √ 2x2 = ( 14 - 2√2 ) : 2 = 7 - √ 2