log5 (4-x)+log5 ( x+3)=log5 10

log5 (4-x) + log5 (x+3) = log5 10 , x∈(-3,4)log5 (4-x)(x+3)= log5 10(4-x)(x+3)=104x+12-x²-3x=10-x²+x+12-10=0-x²+x+2=0x²-x-2=0(x-2)(x+1)=0(a.b=0⇔a=0 ∨ b=0)a)x-2=0, x=2 , 2∈(-3,4)b)x+1=0,x=-1, -1∈(-3,4)Otvet: x=2, x=-1