решите уравнение (2cos^2x-3cosx+1)кореньctgx=0

ОДЗctgx≥0⇒x∈[πn,π/2+πn,n∈z]2cos²x-3cosx+1=0cosx=a2a²-3a+1=0D=9-8=1a1=(3+1)/4=1⇒cosx=1⇒x=2πn+ОДЗ⇒х=2πn.n∈za2=(3-1)/4=1/2⇒cosx=+-π/6+2πn+ОДЗ⇒х=+-π/6+2πn